Solve steady-state and unsteady-state mass balance problems for chemical engineering processes
Feed: 100 kg/h, 40% A, 60% B
Product 1: ? kg/h, 90% A, 10% B
Product 2: ? kg/h, 10% A, 90% B
Overall: 100 = P1 + P2
Component A: 40 = 0.9*P1 + 0.1*P2
Solution: P1 = 37.5 kg/h, P2 = 62.5 kg/h